Re: two questions



Just a comment on the counter idea.
What you are describing is adding two counters that work in a
predictable pattern. So I can't see where that would help to any great
extent.

counters are always predictable, they count from 0 to whatever their data
type allows them to reach, in this case an unsigned 4 byte integer, which is
why there are several counters because a 4 byte number is quite small, each
counter is incremented differently such that if there are 4 counters then it
would increment as follows.

0,0,0,0
0,0,0,1
0,0,0,2
....
....
....
....
0,0,0,4294967295
0,0,1,0
0,0,1,1
0,0,1,2
....
....
....
....

and the incrmentation would continue until all 4 counters have reached
4294967295

to reach the maximum for all 4 counters, there will be 2^127.9 individual
increments

this would mean that for as long as the counter is not repeating itself,
then no matter how many times you use the same K, the subset k will never be
the same.


.



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