Re: Non-Scalar Cryptography - The Emporor is stark naked.

On May 12, 1:06 pm, "Joseph Ashwood" <ashw...@xxxxxxx> wrote:
<austin.oby...@xxxxxxxxxxxxxx> wrote in message

news:0718ea2a-ed07-41cc-9b04-1dea259f2070@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

As you've been told before, in particular by me. You have done nothing here
of any value. Let's just cover your specific claims in this set
"theoretically unbreakable"
It has a key, key is not infinite, therefore key can be bruteforced. I don't
even have to know what cipher it is to know that your opening claim is wrong

"industry and academia remain intractable to overtures for ... discussion on
this matter"
Quite the contrary, we are very open to change, we simply look at your
statements, prove you incorrect, and move on.

Since the rest of your message is completely worthless, I'll leave everyone
with a simple statement taht if you are curious as to the failings, feel
free to search google groups for the last conversation. To spoil the
punchline the claim was made that vectors are not equivalent to scalars, by
diagonalization they are exactly equal, any further examination of the
claims is worthless.
                Joe

The key is invariably equal to the message-length but that is just in
passing. I agree It may be short by comparison with infinity just the
same. What I cannot agree with is your claim that it can be brute
forced when it is being protected by a one-way function. This
function requires a transfer of data from a human memory to a computer
memory in order to specify each and every operand in a brute force
attack on each of the elements of key. Randomness does not even come
into it . The operand is embedded inextricably within each element of
the key thus protecting it. - adacrypt
.