Prime Factor Testing- A Method
- From: Douglas Eagleson <eaglesondouglas@xxxxxxxxx>
- Date: Thu, 28 Feb 2008 20:08:11 -0800 (PST)
z a factorization method was to be understood as allowed.
given p as p = prime 1* prime 2;
Denote a floor as the integer divisor. Allow a loop to exit as the
solved division fails. So real answer simply begs how to prime test
any integer.
Test number z = z+1, divide and if integer solves apply test for a
prime? NO only one test was to be devised. A valid integer as given p
and z. Fast divisor means no divison as a real.. SO all integer as
solvable was to be:
single character naming convention will mean analogy.
char[z] an array of z size a division meant the place. So sort
char[p] as a relative list.
place char[z] a place was to be searched to find z. given a set p
find a z. ANy z. So take the set p and sort such that z exists.
for a= 1 to A loop
for z= 1 to Z loop
if z a=a+1; /*the inner loop increment the outer answer loop
/*a prime test is conducted each incremeent of a*/
if a*z <p then exit inner loop
/*if z increments and is not a prime,exit the inner loop immediately.
z=z+1;
end loop
end loop
Integer multiplication as a rule is fast and loop outer or a appears
the smaller prime to be found.
The advantage was a simple single fast multiplication.
How does this idea look?
Douglas Eagleson
Gaithersburg, MD USA
.
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