Re: The Ultimate - A No-Numbers Dsplacement Cipher -Adacrypt.

On Apr 21, 2:52 pm, j...@xxxxxxxx wrote:
On 21 Apr, 13:28, AdaCrypt <austein.oby...@xxxxxxxxxxxxxx> wrote:





On Apr 21, 12:09 pm, AdaCrypt <austein.oby...@xxxxxxxxxxxxxx> wrote:

On Apr 21, 11:59 am, AdaCrypt <austein.oby...@xxxxxxxxxxxxxx> wrote:

On Apr 21, 11:07 am, AdaCrypt <austein.oby...@xxxxxxxxxxxxxx> wrote:

On Apr 21, 11:03 am, "Dave -Turner" <d...@xxxxxxx> wrote:

This cryptography
is incredible easy to use and understand -Just say the word and I
will send you a secured email for you your perusal.

why not send it here?

Will do - I just need to prepare a short discussion model - a few
hours from now - thanks - adacrypyt

As promised - Adacrypt

Discussion Model of an Email Displacement Encryption Cipher.

This is a screen picture of a cipher I have written that is dedicated
to securing emails. Its application role to emails is secondary here
and is not as important as demonstrating a displacement cipher for
criticism by the Sci crypt community.

My computer page looks like this when RUN is pressed on the program
editor.

" Your encrypted email message will go as a file of cipher-text in an
attachment to an unsecured ordinary covering message"

Please enter the name of your intended email ciphertextfile >

"Email_X.dat" ( a demonstration piece as a message )

Type the text for encryption starting here - to finish the session
type '~' >

Begin >

3456756 8686291 5988408
3877346 7964114 4969533
1299596 7868325 9099594
5986084 8770304 7899527
4977431 8977450 9787448
4094758 7866535 8908779
2985622 6999548 9787438
3949436 8977690 9787612
9876807 5675092 9568221
7686452 9846628 9898883

You wrote >

Your entire file comprising in all
10 characters has been encrypted

Keeping it simple.

1)Each row is a large vector. It is the resultant of two vectors, a)
a change of origin vector and b) a position vector of a point in
space. Before any illegal cryptanalysis can begin, the position
vector component of the row must be established. I contend this is
impossible to find. The latter has a possibility field of vectors that
is a 63 bit number.

I contend that Eve cannot break down this cipher.

Please give this your best shot but be kind enough to give reasons for
your criticisms. - Adacrypt
The software fits on a floppy disc - I will send it to you for your
private experiments if you wish. The programs are written in Ada-95
and I will send you that also - be my guest - Austin

------------------------------------------

So as not play 'cat_n_mouse' with people, the encrypted message above
is the single word " Milestone " - cheers - Adacrypt
__________________________- Hide quoted text -

- Show quoted text -

Also - Adacrypt again

The ciphertext above is a set of non-parallel vectors - this is the
absolute upper limit of Shannon entoropy or in every day language
information entropy - it is a model of maximum entropy for discussion
purposes - I call this saturation entropy - a privately-coined word -
the cipher text just could not contain any more. - Austin.- Dölj citerad text -

- Visa citerad text -

Is that a block cipher?
What is the relation in bytes between plaintext ciphertext given.
1000 bytes plaintext
10 000 bytes plaintext
100 000 bytes plaintext
1 MB plaintext

How much bigger do a the ciphertext get, is it a linear relation, or
was your ciphertext so much bigger than the plaintext because of
blocksize?

What speed does the encryption work with per second, how many bytes
(what cpu you use?)
Can you give us the output for the word "milston" instead of
milestone?
What password was used?
Can you give us the output for a key with +- one bit. Example key
BDA
new keys ADA,CDA
What size of keys can the cipher use/handle?

JT

JT- Hide quoted text -


- Show quoted text -

Is that a block cipher?

No - it is being promoted as a modern version of a one-time pad - A
type of stream cipher perhaps?
- there is one to one plaintext to the vector ciphertext mapping.

What is the relation in bytes between plaintext ciphertext given.

As you can see the ciphertext has 23 or maybe 24 characters to the
single plaintext character - I am using 32-bit aritmetic in my
computer - I have not measured the machine code volume up to now.- is
that ok - let me know

How much bigger do a the ciphertext get, is it a linear relation, or

Yes it's linear with the amount of plaintext.

was your ciphertext so much bigger than the plaintext because of
blocksize?

No - the ratio of plaintext to ciphertext is 99.9% constant at
whatever you see now before you in actual character size.

What speed does the encryption work with per second, how many bytes
(what cpu you use?)

I measure it in characters per second for both encryption and
decryption - this is 7000 per second or thereabouts.
- the cpu is a typical ordinary old home computer job - if its
important I could try and get the exact details for you from Fujitsu
Siemens ( the manufacturers )

Can you give us the output for the word "milston" instead of

You can get this yourself I think just by scoring out the last line
of ciphertext - the vector that represents the letter 'e'.

What password was used?

There is no password as such - to be discussed maybe?

Can you give us the output for a key with +- one bit. Example key
BDA
new keys ADA,CDA

You've lost me here - I am one-cipher man I'm afraid.

What size of keys can the cipher use/handle?

The global key is, like the one-time pad, the same length as the
message. The local keys ( as you see them in front of you on the
posting can have coefficients as large as you like according to the
arithmetic of the computer 32-bit or 64-bit in the Vista for instance.

I hope this is what you explicitly want - let me know if more is
required - regards - Adacrypt

.

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