Re: About RSA Cryptosystem
- From: "Amitabh" <amitabh123@xxxxxxxxx>
- Date: 27 Feb 2007 08:42:55 -0800
On Feb 27, 5:13 pm, "Jian-jie" <jjzhao1...@xxxxxxxxx> wrote:
The RSA Cryptosystem. uses computations in Zn, where n is the product
of two distinct odd primes p and q. For such n, note that φ(n) = (p -
1) (q - 1).
It is easy to prove that ((x)^b)^a=x(mod n) when x belongs to Zn*.But
how to prove the result when x belongs to Zn\Zn*.
Thank you very much!
J-Zhao
Use the CRT. If m is not co-prime to p, then m^(ed) = 0 = m mod p
same with mod q. Thus m^(ed) = m mod p (and mod q)
Also, If p and q are coprime, a = b (mod p), and a=b (mod q), then a =
b mod (pq).
.
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