and now for something completely different.

how effective is this method?

j = 1
do until end of message
Cj = Pj xor Kj xor Ci
i = j
j ++
loop

inversely

j = 1
do until end of message
Pj = Cj xor Kj xor Ci
i = j
j ++
loop

where j and i are counters. this is a byte by byte method. assume that P, C
and K are the same length.


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