Re: Need Graph Isomorphism Algorithm De-bunked
- From: Mike Amling <nospam@xxxxxxxxxx>
- Date: 27 Sep 2006 22:47:29 EDT
Ben Livengood wrote:
fgrieu wrote:Mike Amling wrote:...An alternative to step 6 is to output the graph in generic
order based on a sort of the results, making a much shorter
and useful representative of the graph's equivalence class
(this has been suggested by Bill Cox).
I however fail to convince myself that this is equivalent;
or that the "compare graph's hash" variant never falsely
declare graphs isomorphic, or that the "compare sorted
graphs" variant never falsely declare graphs non-isomorphic.
François Grieu
I think it is sufficient to represent the graph over the equivalence
class of its vertices. Let N be the number of equivalence classes over
the vertices in the graph.
Equivalence under what relationship? Is this related to automorphism?
Let A be a modified N*N adjacency matrix.
such that A[i,j] is the number of edges from vertices in equivalence
class i to vertices in equivalence class j. To handle vertices with
zero degree the original number of vertices will have to be output as
well.
I don't know much graph theory, so I apologize if this representation
already has a name or a better description, or if it doesn't actually
work.
Ben Livengood
- References:
- Need Graph Isomorphism Algorithm De-bunked
- From: Bill Cox
- Re: Need Graph Isomorphism Algorithm De-bunked
- From: Bill Cox
- Re: Need Graph Isomorphism Algorithm De-bunked
- From: Francois Grieu
- Re: Need Graph Isomorphism Algorithm De-bunked
- From: Bill Cox
- Re: Need Graph Isomorphism Algorithm De-bunked
- From: fgrieu
- Re: Need Graph Isomorphism Algorithm De-bunked
- From: Bill Cox
- Re: Need Graph Isomorphism Algorithm De-bunked
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- Re: Need Graph Isomorphism Algorithm De-bunked
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