Re: JSH: Hyperbolic factoring method

john wrote:
<jstevh@xxxxxxx> wrote in message
news:1147669282.128851.126270@xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
tomstde...@xxxxxxxxx wrote:
jst...@xxxxxxx wrote:
I haven't been drinking. I just never did post on Usenet the proper
equations without errors in them.

The first step is denial. Please brother James, join the program.

You people are too weak-minded to understand much of anything.

I assume your math works, it's your algorithm I question.

Anyone can say "write nK as x^2 - y^2, there you've factored". It's
figuring out an algorithm that is the tricky part. I doubt you're too
obtuse to realize this. You're just too much of a COMPLETE FUCKING
*** to give it a rest.

I think the human brain is too limited in its circuitry.

Are we to assume that James is not a human?

Tom

You managed to change my mind.

Here are the corrected equations:

T = (x+(k_3 -1)y - vz)(x + y + vz)

x^2 + k_3 xy + k_1 y^2 = k_2 z^2

(2(v^2 - k_2)z - (k_3 - 2)vy)^2 = (((k_3 - 2)^2 - 4(k_1 - k_3 + 1))y^2
+ 4T)v^2 + 4k_2(k_1 - k_3 + 1)y^2 - 4Tk_2

k_3=1, won't work, and using k_3=2, breaks a wing, but k_3 = 3, might
work, who knows.


doesn't work for k_2 = 3 either

Fine. I don't really care at this point. Oh, and it should have been
that with k_3 = 1 it breaks a wing, but won't work with k_3 = 2.

Interestingly enough, if I gave the correct equations it WILL factor at
times.

That's an absolute which can be verified by simply going backwards with
a known factorization of T, to find x, y and z, and from them find the
other variables.

The issue is, how well does it work?

If the poster I'm replying to actually checked versus thinking this is
just some joke and he could reply with nonsense, and found it factored
a low percentage of the time, then that would be of interest.

My own argument has been that it will non-trivially factor 25% of the
time.

If it doesn't then fine. I don't care. If it does, then, well, better
run to liquidate all of your stocks before the world finds out.


James Harris

.