Re: Quickly finding large primes

Besides the proof is trivial that given

p^2 - 2 = 0 mod p

factors of p^2 - 2 can only be primes with a quadratic residue of 2.

Of course, the proof is *also* trivial that given

p^2 - 2 = 0 mod p

then p *equals* 2.

I think it's funny that James is too dumb to notice this!


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