Re: Surrogate factoring, experimental process

From: David Eather (eather_at_tpg.com.au)
Date: 02/06/05 

Date: Mon, 7 Feb 2005 07:34:42 +1000

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James,
if you're not man enough to apologise to the people you insulted then
you have nothing more to say.
I see you are following last years script (oh, woe is me all that
work for nothing). Can you show how much "different" your current
work is now, compared to last year (last year you were doing extreme
maths, talking to the NSA and describing everyone else as fools, and
then it came out that you couldn't find out how to efficiently select
parameters for your program - how and by how much is this time
different?
Don't go away angry - just go away.

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jstevh@msn.com wrote:
> Taking a break from the research, and it amazes me how you can
> think you have a theory worked out, and think you have a handle on
> it, but then find surprises when you try to implement it.
>
> The necessary role of experimental mathematics here is interesting
> as well, as I think it'd be difficult to work out how to actually
> get surrogate factoring to work, just by thinking about it.
>
> You need to experiment.
>
> In holding on to hope about my own theory, I rely on the parts of
> that theory that are well worked out. And a very important result
> I have has to do with a variable I call A.
>
> Remember surrogate factoring involves the two quadratics:
>
> yx^2 + Ax - M^2 = 0
>
> and
>
> yz^2 + Az - j^2 = 0
>
> and looking for solutions where given integers A, j, and M, where M
> is your target to be factored, you find *rational* y, x and z.
>
> The surrogate in the factoring is T, where T = M^2 - j^2, and the
> idea is to pull out the factorization of M, from the factorization
> of T.
>
> A massively important result I have is that other than needing to
> be greater than zero the value of A does not matter.
>
> That is a huge result that the theory shows over and over again,
> which shows this idea should work.
>
> But there is theory, and there is implementation.
>
>
> James Harris

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