Re: MD5 Cracking

From: Barry Fawthrop (barryNOSPAM_at_ttienterprises.orgINVALID)
Date: 03/28/04 

Date: Sun, 28 Mar 2004 02:57:43 GMT

Understanding then that one has to brute force and MD5 let me ask this?

If I'm right to create an MD5 Hash there are four parameters, as such
MD5 [ (Challenge,Password), HashCode ] = MD5_Hash

Thus If knowing only two parameters Challenge and MD5_Hash, one would brute
force since you know only two out of three parameters

BUT what if
If you knew three: Challenge1, Password1, and MD5_Hash1

Could you use this to find the HashCode, which if I'm right is standard,
then now knowing HashCode, use a non brute force method

with Challenge2, HashCode and MD5_Hash2, to find Password2
Is the logic right or not, would appriecate it being clarified if possible

Thanks in Advance

B

Relevant Pages

  • Re: MD5 Cracking
    ... ]Understanding then that one has to brute force and MD5 let me ask this? ... ]If I'm right to create an MD5 Hash there are four parameters, ... ]then now knowing HashCode, use a non brute force method ...
    (sci.crypt)
  • Re: pass help
    ... not uncommon as a key size. ... But it doesn't have to be a password at all: it could be the MD5 hash ... and "brute force". ... (There are other weaknesses with MD5 though; ...
    (comp.security.misc)
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