Re: generators be bound
From: Mok-Kong Shen (mok-kong.shen_at_t-online.de)
Date: 10/24/03
- Next message: Andrew Swallow: "Re: Is it OK with newbie questions in this NG?"
- Previous message: Kristian Olsen: "Is it OK with newbie questions in this NG?"
- In reply to: Tom St Denis: "generators be bound"
- Next in thread: Marcel Martin: "Re: generators be bound"
- Reply: Marcel Martin: "Re: generators be bound"
- Reply: Tom St Denis: "Re: generators be bound"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ] [ attachment ]
Date: Fri, 24 Oct 2003 03:50:09 +0200
Tom St Denis wrote:
>
[snip]
> So what should I have said to mean a generator of a sub-group of a given
> order?
My math knowledge is poor and maybe I misunderstood you,
but, if you have a subgroup (of whatever order) of a cyclic
group, then it is also cyclic and there must be an element
of it that generates that subgroup and that element is by
definition a generator of that subgroup. Or am I missing
something?
M. K. Shen
- Next message: Andrew Swallow: "Re: Is it OK with newbie questions in this NG?"
- Previous message: Kristian Olsen: "Is it OK with newbie questions in this NG?"
- In reply to: Tom St Denis: "generators be bound"
- Next in thread: Marcel Martin: "Re: generators be bound"
- Reply: Marcel Martin: "Re: generators be bound"
- Reply: Tom St Denis: "Re: generators be bound"
- Messages sorted by: [ date ] [ thread ] [ subject ] [ author ] [ attachment ]
Relevant Pages
|