Re: [Newbie] Prime factorization question
From: Mxsmanic (mxsmanic_at_hotmail.com)
Date: 10/10/03
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Date: Fri, 10 Oct 2003 05:14:33 +0200
Gregory G Rose writes:
> I think you have a problem understanding large
> numbers. Yes, there is a chance of it happening.
> But probably not in this universe.
Should I interpret this to mean that the decision to develop the modulus
as the product of two equal-sized primes is made simply to reduce the
possibility of a failure of the cipher and/or factorization of the
modulus, and not because a modulus with exactly two prime factors is
essential in some way to the proper function of the cipher?
If so, then I presume that a modulus that has more than two factors
(i.e., that is the product of something other than exactly two primes)
would still work for RSA, but with a far greater likelihood of failure,
and with far greater susceptibility to cracking through factorization.
And conversely, it would also mean that even with ideal prime factors,
RSA is not completely sound, because it can still fail if one of the
factors of the modulus is also a factor of the message being encrypted.
Is this all correct?
-- Transpose hotmail and mxsmanic in my e-mail address to reach me directly.
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