Actually how simple is VMPC?
From: Bartosz Zoltak ()_at_vmpcfunction.com)
Date: 08/29/03
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Date: Fri, 29 Aug 2003 19:59:27 +0200
I would like to write false claims in the article on VMPC, which is to be
printed in one of the popular computer magaizes in Poland, so I would like
to make sure simple the VMPC function actually is.
Let alone - for the moment - whether it is one-way - I would just like to
say in the article how VMPC - IF in fact it was agreed to be (or somehow,
unlikely, proven) one-way - compares to the known one-way functions in terms
of simplicity.
Q,P - 256 element permutations,
VMPC: Q[x]=P[P[P[x]]+1]. It takes 3 elementary logical steps (subjective
measure - the steps are like "take Y-th element of P and store it in
variable Z") which all can be also written with 3 MOV assembler instructions
to compute each element of Q, so it totals in 256*3=768 MOV instructions /
basic logical operations to get Q from P or 3 per byte.
How doeas this copare to the kown one-way functions? Hash functions look
more complicated (though VMPC function is no competition to hash functions),
factoring - multiplying two big numbers is probably more complex than
computing VMPC?
Any indications on the simplest known one-way functions?
BTW, as some recommended, I organized the content (related to VMPC function
only) of the website into a paper (VMPCfunction.PS or .PDF, also in ZIP
format) and it is available for download at
www.vmpcfunction.com/function.htm . The paper contains the same information
as the website,so it is up to which form one finds more conveniet, if one
would like to read about the VMPC function. A paper on the VMPC cipher will
be prepared a bit later.
Thanks for help
Bartosz
-- Bartosz Zoltak http://www.vmpcfunction.com QPbzoltak@vmpcfunction.com without "QP"
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