Re: Outlook cannot reply to signed email without certificate
From: David Cross [MS] (dcross_at_online.microsoft.com)
Date: 01/14/05
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Date: Fri, 14 Jan 2005 03:41:39 -0800
Unfortunately, this is how Outlook works. I do not know a workaround for
you in this case.
-- David B. Cross [MS] -- This posting is provided "AS IS" with no warranties, and confers no rights. Top Whitepapers: Auto-enrollment whitepaper: http://www.microsoft.com/technet/prodtechnol/windowsserver2003/technologies/security/autoenro.mspx Best Practices for implementing Windows Server 2003 PKI: http://www.microsoft.com/technet/prodtechnol/windowsserver2003/technologies/security/ws3pkibp.mspx Troubleshooting Certificate Status and Revocation whitepaper: http://www.microsoft.com/technet/security/topics/crypto/tshtcrl.mspx Windows Server 2003 web enrollment and troubleshooting guide: http://www.microsoft.com/technet/prodtechnol/windowsserver2003/technologies/security/webenroll.mspx Windows Server 2003 web enrollment and troubleshooting guide: http://www.microsoft.com/technet/prodtechnol/windowsserver2003/technologies/security/webenroll.mspx "selkin" <stewart_elkin@hotmail.com> wrote in message news:1105605704.001300.242440@c13g2000cwb.googlegroups.com... > When a normal (no certs) user receives a signed email from someone > else, Outlook will not let them reply without having their own > certificates. These certs are not necessary to reply. > > As the only holder of an email signing certificate, I should be able to > send a signed email to anyone else in the company and they will be able > to verify it. This works fine. However, when any other user then tries > to REPLY to this signed email, Outlook intervenes with a prompt for > them to get a new digital ID, i.e. asking them to configuire their > email and signing certs. Why is this necessary? (Even when the second > user gets their own certs, they can reply to the original mail withouth > signing their own reply , thus proving that they do not need any certs > to reply). > Does anyone have any insight into what is happening here? Thanks. >
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