From: CryptEncrypt Input block size (Darren_at_discussions.microsoft.com)
Date: Thu, 5 Aug 2004 23:09:09 -0700
When using CryptEncrypt to encrypt data, it takes in a
BYTE* of plaintext to be encrypted. Looking at the sample
code in MSDN, the input block size is 1000 - 1000 %
ENCRYPTION_BLOCK_SIZE. As far as I understand, block
cipher algorithms typically have an input block size of
around 64-bit or 128-bit... definitely not as large as
1000-bytes (or so).
Does this mean that the input block size should only be 64-
bit or 128-bit (or whatever size the algorithm requires)?
Or is the CryptEncrypt function capable of accepting large
chunks of data as long as it is a multiple of the block
size (and it will break the data up into the proper block
sizes and run through the required number of passes in the
one function call)?