Re: How is .net generating extra bits in MD5?
From: Valery Pryamikov (Valery_at_nospam.harper.no)
Date: 01/21/05
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Date: Fri, 21 Jan 2005 23:25:58 +0100
Hi,
PasswordDeriveBytes does the same thing as CryptDeriveKey and actually
involves 3 hashes:
K' = H(password)
K = H(K' XOR {0x36}) || H(K' XOR {0x5C})
where H is hash algorithm, || - concatenation and K' is intermediate key.
-Valery.
http://www.harper.no/valery
"Pete" <jpeteb@hotmail.com> wrote in message
news:1106337228.327388.91720@z14g2000cwz.googlegroups.com...
> Hi,
>
> I have a piece of .net code I am trying to understand. It creates a MD5
> hash then requests 256 bits from the hash, where MD5 only generates 128
> bits. I've looked at the hash with another non-.net piece of code and
> the first 128 bits match up correctly. How is Microsoft creating the
> second 128 bits? I cannot seem to figure that out. Here is a code
> fragment in C#:
>
> string passPhrase; // password string
> string saltValue; // salt string
> string hashAlgorithm; // set to "MD5"
> int passwordIterations; // set to 2
> int keySize; // set to 256
>
> byte[] initVectorBytes = Encoding.ASCII.GetBytes(initVector);
> byte[] saltValueBytes = Encoding.ASCII.GetBytes(saltValue);
>
> PasswordDeriveBytes password = new PasswordDeriveBytes(
> passPhrase,
> saltValueBytes,
> hashAlgorithm,
> passwordIterations);
> byte[] keyBytes = password.GetBytes(keySize / 8);
>
>
> TIA for any help.
>
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