From: Ron Cicotte (email@example.com)
From: "Ron Cicotte" <firstname.lastname@example.org> Date: Mon, 21 Apr 2003 18:01:23 -0400
I am using forms authentication and it seems to work fine except for the
FormsAuthentication.Signout(). I have a login page with the following code
in the Page_Load function:
private void Page_Load(object sender, System.EventArgs e)
//utilities for managing database I/O
// check forms authentication and set isloggedin = true if the user is
// auto logout when coming back to this page after logging in
isLoggedIn = false;
uid = Int32.Parse(ViewState["uid"].ToString());
isLoggedIn = (bool)ViewState["IsLoggedIn"];
LoginCookies tests to see if the user is logged in using the
Request.IsAuthenticated attribute and sets a page var (bool isLoggedIn)
based on the result. The problem is that the the SignOut() method is not
removing the authentication cookie as expected. Request.IsAuthenticated
always returns true. I have a watch on the IsAuthenticated attribute in my
VS debugger and it does not change after the Signout() method is invoked. I
test it immediately following the repost after redirection and it is still
What can I do?
I have posted this elswhere in this newsgroup but this seemed an appropriate
place to bring it up again.
Thanks for whatever advice you may have.
"Victor Garcia Aprea [MVP]" <vga@NOobiesSPAM.com> wrote in message
> Hi Brian,
> Take a look at the FormsAuthentication.SignOut method,
> Victor Garcia Aprea
> Microsoft MVP | ASP.NET
> "Brian Morris" <email@example.com> wrote in message
> > I have an application that I am using FormsAuthentication on. I don't
> > understand the process and copied the code to make it work from a book.
> > What I want to make is a Logout button that destroys their
> > I would guess that this is pretty easy since using this authentication
> > method was pretty easy in the first place.
> > Can someone please provide me with the syntax to make the application
> > I am no longer authenticated. I don't want to have my client close
> > browser and am not sure that would work anyway. I haven't tried that
> > because I am still developing my app.
> > tia,
> > -brian