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From: Wolfgang Schelongowski (spamtrap@xivic.prima.de)Date: 10/30/02
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From: spamtrap@xivic.prima.de (Wolfgang Schelongowski) Date: 30 Oct 2002 20:22:08 +0100
In <868z0g3w7g.fsf@potato.vegetable.org.uk>
Tim Haynes <usenet@stirfried.vegetable.org.uk> writes:
>spamtrap@xivic.prima.de (Wolfgang Schelongowski) writes:
[somebody else Tim graciously snipped wrote]
>>>> Can you give pointers to the source where it oversteps the bounds described
>>>> above?
>>
>> Where it says:
>> | To remind you, the DeScan listening
>> |agent is a very small binary
>>
>> Where's the source, man? IOW they don't reveal to us what they really do.
>> That's *B*A*D*.
>The source is right in front of your eyes.
Obviously you have no understanding of the basics of programming. So just
for you, in a nutshell:
#include <linux/module.h>
#include <linux/fs.h>
...
static void sr_release(struct cdrom_device_info *cdi)
{
if (scsi_CDs[MINOR(cdi->dev)].sector_size > 2048)
sr_set_blocklength(MINOR(cdi->dev),2048);
sync_dev(cdi->dev);
scsi_CDs[MINOR(cdi->dev)].device->access_count--;
if (scsi_CDs[MINOR(cdi->dev)].device->host->hostt->module)
__MOD_DEC_USE_COUNT(scsi_CDs[MINOR(cdi->dev)].device->host->host
if(sr_template.module)
__MOD_DEC_USE_COUNT(sr_template.module);
}
is an example of a part of a source. In this context the file name
usually ends with ".c", and a compiler produces the binary from it.
>There's nothing wrong with use
>of the word `binary' when describing a binary.
I never said it was. But as long as they don't give us the source from
which it is compiled the only way to find out what the binary really
does is to disassemble it and ma nually decompile it. The latter is a
very timeconsuming operation which only very few programmers can do
successfully.
HTH. HAD.
-- "Some people are heroes. And some people jot down notes." -- Terry Pratchett, The Truth
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