Re: procfs + chmod = no go
From: Daniel Ben-Zvi (acid_at_tapuz.co.il)
Date: 03/01/04
- Previous message: Robert Watson: "Re: procfs + chmod = no go"
- In reply to: Andy Gilligan: "Re: procfs + chmod = no go"
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To: "Andy Gilligan" <andy@glbx.net> Date: Mon, 1 Mar 2004 16:38:54 +0200
It should accomplish the same thing,
but for some reason (and maybe thats how it was intended to be) the whole
process tree can still be viewed from /proc
This may be considered a bug but can be easily fixed with a small kernel
patch.
----- Original Message -----
From: "Andy Gilligan" <andy@glbx.net>
To: <freebsd-security@freebsd.org>
Sent: Monday, March 01, 2004 2:50 PM
Subject: Re: procfs + chmod = no go
> On Mon, 1 Mar 2004 at 12:27, Dag-Erling Smørgrav wrote:
> > "Jimmy Scott" <admin@inet-solutions.be> writes:
> > > Is this possible on FreeBSD 4.9 ? Can't find anything about it in the
> > > manual pages. Just want to prevent lusers from running:
> > >
> > > for file in /proc/*/cmdline; do cat $file; echo; done
> >
> > Why? They can get the same information from ps(1) or the kern.proc
> > sysctl tree.
> >
> > (in 5.2, you can set security.bsd.see_other_uid to 0 to prevent users
> > from seeing other users' processes)
>
> Surely kern.ps_showallprocs would accomplish the same thing in 4.x ?
>
> -Andy
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- Previous message: Robert Watson: "Re: procfs + chmod = no go"
- In reply to: Andy Gilligan: "Re: procfs + chmod = no go"
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